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Electricity MCQ Class 10 Physics

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Electricity mcq with Solution

1. True test of charging is :

(A) Attraction                                                

(B) Repulsion

(C) Both attraction & repulsion                      

(D) None of the above

Solution

Ans.     (B)

Sol.      Repulsion is a true test for electrification as one charged body can attract another uncharged body due to induction also.

2. Which of the following charge on an object is not possible :

(A) 3.2 × 10-19C                                             

(B) 4.8 × 10-19C

(C) 5.4 × 10-19 C                                            

(D) 8.0 × 10-19C

Solution

Ans.     (C)

Sol.      Charge is quantised so, charge on any body should always be an integral multiple of charge on an electron.

3. A body is given positive charge :

(A) Its mass will increase                                

(B) Its mass will decrease

(C) Its mass will remain same                         

(D) None of these

Solution

Ans.     (B)

Sol.      Body acquires positive charge due to removal of electrons so its mass will decrease.

4. Charge on 6.25 × 1018 electrons is :

(A) 1 coulomb                                               

(B) 2 coulomb

(C) 10 coulomb                                             

(D) 0.5 coulomb

Solution

Ans.     (A)

Sol.      Charge on one electron  = 1.6 × 10–19 C

Charge on 6.25 × 1018 electrons = {6.25 × 1018}×{1.6 × 10–19} = 1C

5. Which of the following is the S.I. unit of charge :

(A) Coulomb                                                  

(B) Ampere

(C) Volt

(D) Newton

Solution

Ans.     (A)

Sol.      S.I. unit of charge is coulomb.

6. Joule/coulomb is the unit of :

(A) Electric potential                                       

(B) Electric current

(C) Force                                                       

(D) Work

Solution

Ans.     (A)

Sol.      S.I. unit of electric potential is J/C.

7. Tiny bits of paper are attracted by a charged comb due to :

(A) Conduction                                               

(B) Induction

(C) Convection                                              

(D) Radiation

Solution

Ans.     (B)

Sol.      Tiny bits of paper are attracted by a charged comb due to Induction.

8. Law which gives magnitude of force between two charges is :

(A) Ohm’s law                                                

(B) Faraday’s Law

(C) Coulomb’s law                                          

(D) None of these

Solution

Ans.     (C)

Sol.      Coulomb’s law gives the magnitude of electric force between two charged particles.

9. When a glass rod is rubbed with silk cloth :

(A) Glass rod gets positively charged             

(B) Silk cloth gets negatively charged

(C) Glass rod looses electrons

(D) All are correct

Solution

Ans.     (D)

Sol.      When a glass rod is rubbed with silk cloth, it acquires positive charge while silk cloth gets negatively charged.

10. Cause of positive charge on a body is :

(A) Excess of electrons                                  

(B) Lack of electrons

(C) Excess of protons                                    

(D) Lack of protons

Solution

Ans.     (B)

Sol.      A body gets positively charged by loosing electrons.

11. All equipments in households have :

(A) Same potential difference                         

(B) Same current

(C) Same power                                             

(D) Both (A) & (C)

Solution

Ans.     (A)

Sol.      Same potential difference.

12. A positive charge released from rest :

(A) moves towards the regions of lower potential

(B) moves towards the regions of higher potential

(C) moves towards the regions of equal potential                                                        

(D) Does not move

Solution

Ans.     (A)

Sol.      Positive charge always moves towards the region at lower potential from higher potential.

13. A battery is used to :

(A) Maintain a potential difference                   

(B) Measure electric current

(C) Measure electric potential                          

(D) Safeguard against short circuit

Solution

Ans.     (A)

Sol.      Battery is used to maintain potential difference.

14. Two electric bulbs have resistances in the ratio 1 : 2. If they are joined in series, the energy consumed in them are in the ratio ………… :

(A) 1 : 2                                                         

(B) 1 : 1

(C) 2 : 1                                                         

(D) 4 : 1

Solution

Ans.     (C)

Sol.      We know P = I2R

In series combination current is same for two resistances

∴  P \propto R \Rightarrow \frac{{{P_1}}}{{{P_2}}} = \frac{{{R_1}}}{{{R_2}}} \Rightarrow \frac{{{R_1}}}{{{R_2}}} = \frac{1}{2}  .

15. On a body, charge can be produced by :

(A) Friction                                                     

(B) Induction

(C) Conduction

(D) All of the above

Solution

Ans.     (D)

Sol.      Charge can be prodcued by any of A, B, C. So answer is D.

16. If  distance between two charges increases, the value of force between them :

(A) Increases                                                  

(B) Decreases

(C) Remains un changed                                 

(D) May increase or decrease

Solution

Ans.     (B)

Sol.      F \propto \frac{1}{{{r^2}}} so when r increases, F decreases.

17. The path of free electron in a metal is :

(A) Parabolic                                                  

(B) Circular

(C) Straight line                                              

(D) Zigzag

Solution

Ans.     (D)

Sol.      Zigzag (random motion).

18. Electric potential at point ‘A’ is 10 V & at point B is – 10 V. Find the work done by external agent in carrying 1 × 10–6 C of charge from A to B without acceleration ?

(A) 20 × 10–6 J                                               

(B) – 20 × 10–6 J

(C) 10 × 10–6 J                                               

(D) – 10 × 10–6 J

Solution

Ans.     (B)

Sol.      W = qΔV = 1 × 10–6 [– 10 – (+ 10) ] = – 20 × 10–6

19. When a body is negatively charged by friction, it means :

(A) The body has acquired excess of electrons                                                           

(B) The body has acquired excess of proton

(C) The body has lost some electrons             

(D) The body has lost some neutrons

Solution

Ans.     (A)

Sol.      Negative charge results from excess of electrons.

20. When a fuse is rated 8A, it means :

(A) It will not work if current is lessthan 8A

(B) It has a resistance of 8w                            

(C) It will work only if current is 8A

(D) It will melt if current exceeds 8A

Solution

Ans.     (D)

Sol.      It will melt if current exceeds 8A.

21. Which of the following graph represents an ohmic device :

(A) mcq on electricity class 10     

(B) 1.2

(C) 1.3  

(D) 1.4 

Solution

Ans.     (A)

Sol.      For ohmic device I α V so graph is straight line and slope indicates electrical resistance.

22. Resistance depends upon:

(A) Nature of material of conductor                 

(B) Length of conductor

(C) Area of cross section of conductor           

(D) All of the above

Solution

Ans.     (D)

Sol.      R =  \rho .\frac{l}{A}so answer is D.

23. How many electrons constitute current of one milliampere:

(A) 6.25 × 106                                                 

(B) 6.25 × 1012                                               

(C) 6.25 × 109                                                 

(D) 6.25 × 1015

Solution

Ans.     (D)

Sol.      N = \frac{{1 \times {{10}^{ - 3}}}}{{1.6 \times {{10}^{ - 19}}}} = 6.25 \times {10^{15}}

24. An aluminium wire of definite length is stretched so that it’s diameter becomes half of initial diameter. Then what is it’s new resistance :

(A) Double                                                     

(B) Four times

(C) Eight times                                               

(D) Sixteen times

Solution

Ans.     (D)

Sol.      Volume (A × l) remains constant on stretching

d2   =\frac{{{d_1}}}{2} ;     A2 =\frac{{{A_1}}}{4} ;   {l_2} = 4 l1   R2 = 16R1

25. Variation of current (I) and voltage (V) in a conductor has been shown in Fig. The resistance of the conductor is :

mcq on electricity class 10

(A) 1Ω  

(B) 2Ω

(C) 3Ω  

(D) 4Ω

Solution

Ans.     (C)

Sol.      R = \frac{{\Delta V}}{{\Delta I}} = \frac{{12}}{4} = 3\Omega

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