kedarraj

MATHEMATICS (BASIC MATHS) ONLINE QUIZ FOR IIT-JEE

In this section provides Mathematics Basic Maths Online Quiz for IIT-JEE students. This quiz is very useful for exam practice purpose.

General Instructions:-

  • This Quiz contains 10 Multiple Choice questions.
  • You will be awarded 1 marks for Correct Answer.
  • No negative marks will be awarded in this Quiz.
  • You can see your result instantly After submitted the Quiz.
  • Please give your valuable comments. 
12
Created on

Basic Maths

Baisc Maths Quiz

1 / 10

The solution set of the inequality \frac{x}{{x-2}} > \frac{1}{{x + 3}} is :

 

2 / 10

If x(x + 1) (x – 2) (x – 3) \geqslant 0 then exhaustive set of values of x is :

3 / 10

The set of real values of ‘x’ satisfying \frac{2}{{{x^2}-x + 1}}-\frac{1}{{x + 1}}-\frac{{2x-1}}{{{x^3} + 1}}\,\, \geqslant \,\,0

4 / 10

The equation :

\frac{{2{x^3}-3{x^2} + x + 1}}{{2{x^3}-3{x^2}-x-1}} = \frac{{3{x^3}-{x^2} + 5x-13}}{{3{x^3}-{x^2}-5x + 13}} has

5 / 10

The set of values of x satisfying \frac{{{{(x-3)}^4}{{(5x-9)}^2}(x + 1)}}{{{{(2x + 1)}^6}(x-3)}}\,\, \geqslant \,0, is

6 / 10

\frac{{{{\left( {x-4} \right)}^{2005}}{{(x + 8)}^{2008}}(x + 1)}}{{{x^{2006}}{{(x-2)}^3}{{(x + 3)}^5}(x-6){{(x + 9)}^{2010}}}} \leqslant 0

7 / 10

The number of solution of the given equation : x\, + \,\frac{1}{{x\, - 2}}\, = \,2\, + \,\frac{1}{{x\, - \,2}}

8 / 10

Smallest positive integral value of x satisfying \frac{{({x^2} - 1)({x^2} - 4){{(x - 3)}^2}(x - 5)}}{{(x + 3)(x - 6)}} > 0 is :

9 / 10

The solution set of  \frac{{2x}}{{2{x^2} + 5x + 2}} > \frac{1}{{x + 1}} is :

10 / 10

The values of x for which \frac{1}{{x - 1}} > \frac{1}{{x + 1}} belongs to

 

Your score is

The average score is 24%

0%

Click Here : Mathematics Function Revision Notes for IIT-JEE
Click Here : Mathematics Function Revision All Type Question for IIT-JEE

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top
Scroll to Top